Funatic Maths

3d-trig

  • Written on
    - Paper 2

    Question 7

    A landscape artist plans to plant flowers within two concentric circles around a vertical light pole PQPQ. RR is a point on the inner circle and SS is a point on the outer circle. RR, QQ and SS lie in the same horizontal plane. RSRS is a pipe used for the irrigation system in the garden.
    • The radius of the inner circle is rr units and the radius of the outer circle is QSQS.
    • The angle of elevation from SS to PP is 3030^{\circ}.
    • RQ^S=2xR\hat QS=2x and PQ=3rPQ=\sqrt{3}r
    Image
    7.17.1 Show that QS=3rQS=3r (3)(3)
    7.27.2 Determine, in terms of rr, the area of the flower garden. (2)(2)
    7.37.3 Show that RS=r106cos2xRS=r\sqrt{10-6\cos{2x}} (3)(3)
    7.47.4 If r=10r=10 metres and x=56x=56^{\circ}, calculate RSRS. (2)(2)
    [10]\textbf{[10]}
  • Written on
    - Paper 2

    Question 7

    The diagram below shows a solar panel, ABCDABCD, which is fixed to a flat piece of concrete slab EFCDEFCD. ABCDABCD and EFCDEFCD are two identical rhombuses. KK is a point on DCDC such that DK=KCDK=KC and AKDCAK\perp DC. AFAF and KFKF are drawn. AD^C=CD^E=60A\hat DC=C\hat DE=60^{\circ} and AD=xAD=x units.
    Image
    7.17.1 Determine AKAK in terms of xx. (2)(2)
    7.27.2 Write down the size of KC^FK\hat CF. (1)(1)
    7.37.3 It is further given that AK^FA\hat KF, the angle between the solar panel and the concrete slab, is yy. Determine the area of ΔAKF\Delta AKF in terms of xx and yy. (7)(7)
    [10]\textbf{[10]}